What is the maximum momentum of a rocket with given exhaust speed and mass?

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SUMMARY

The maximum momentum of a rocket, which starts at rest and ejects exhaust at speed u, occurs when the mass of the rocket (including unused fuel) is optimized. The momentum is defined by the equation p=mv, where v is derived from the conservation of momentum, leading to v=uln(M/m). The differentiation of momentum with respect to mass yields the equation dp/dm=u[ln(M/m)-1/m^2]. To find the mass that maximizes momentum, setting dp/dm to zero is essential, although solving this equation requires careful application of the chain rule to ensure dimensional consistency.

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Homework Statement


A rocket that starts at rest with mass M ejects exhaust at a given speed u. what is the mass of the rocket(including unused fuel) when its momentum is maximum?


Homework Equations



p=mv

The Attempt at a Solution


well basically i used conservation of momentum to get the velocity of the rocket with respect to mass. after doing all the integrating work i got v=uln(M/m) assuming that m is the mass of the rocket at a later time. plugging the velocity into the p=mv formula i differentiate with respect to mass where the equation becomes dp/dm=u[ln(M/m)-1/m^2]. now i set dp/dm to zero to try to find the mass needed for a max momentum but unfortunately the dp/dm equation isn't easy to solve due to the "ln" function. Am i doing something wrong here?
 
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aznwei said:
... the equation becomes dp/dm=u[ln(M/m)-1/m^2].

I don't believe you took the derivative correctly because dp/dm must have dimensions of speed. Your expression does not. Remember the chain rule.
 

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