What is the Maximum Pressure Exerted by a Block of Niobium on One of its Faces?

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SUMMARY

The maximum pressure exerted by a block of Niobium, with a density of 8570 Kg/m³ and dimensions of 3 cm, 4 cm, and 5 cm, can be calculated using the formula for pressure, P = F/A. The force (F) is derived from the weight of the block, which is determined by its volume and density. The volume of the block is 60 cm³, leading to a weight of 0.5142 N, and when stood upright on its 3 cm x 4 cm face, the area is 12 cm². Thus, the maximum pressure is 42.85 N/m².

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A block of Niobium, with density 8570 Kg/m^3 has sides of length 3cm, 4cm and 5cm. What is the max pressure that can be exerted by this block when it is stood upright on one of it's faces?
 
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Please follow the rules of this forum and use the template when you seek help with homework. Show us the relevant equations and tell us what you tried and what you think about the problem. We just don't give answers away.
 
Ah it's cool, I think I figured it out, I just didn't think about one thing.
And I didn't realize about the template, I will ensure I follow it next time!
 

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