What is the Maximum Pressure Exerted by a Block of Niobium on One of its Faces?

  • Thread starter Thread starter Pronitron
  • Start date Start date
  • Tags Tags
    Pressure
AI Thread Summary
To calculate the maximum pressure exerted by a block of Niobium on one of its faces, the relevant equations involve determining the weight of the block and the area of the face in contact with the surface. The block's volume is found by multiplying its dimensions, and its weight is calculated using the density. The pressure is then derived by dividing the weight by the area of the face. The discussion highlights the importance of following forum guidelines and using the correct problem-solving template. The user acknowledges their oversight regarding the template and expresses that they have made progress in understanding the problem.
Pronitron
Messages
8
Reaction score
0
A block of Niobium, with density 8570 Kg/m^3 has sides of length 3cm, 4cm and 5cm. What is the max pressure that can be exerted by this block when it is stood upright on one of it's faces?
 
Physics news on Phys.org
Please follow the rules of this forum and use the template when you seek help with homework. Show us the relevant equations and tell us what you tried and what you think about the problem. We just don't give answers away.
 
Ah it's cool, I think I figured it out, I just didn't think about one thing.
And I didn't realize about the template, I will ensure I follow it next time!
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top