What is the Maximum Radius for a Bucket of Water in Circular Motion?

AI Thread Summary
To determine the maximum radius for a bucket of water swung in a vertical circle, the centripetal force equation Fc = mv^2/r is relevant. The mass of the bucket is 3.75 kg, and the speed at the top of the loop is 6.20 m/s. The gravitational acceleration should be considered as g = -9.81 m/s², assuming the scenario takes place on Earth. The discussion emphasizes understanding the relationship between centripetal force and gravitational force to solve for the radius. Clarification on the formulas and concepts is necessary for effective problem-solving.
Redjakk1
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Homework Statement



A 3.75 kg bucket pile of water is swung in a vertical circle. If the speed of the bucket at the top of the loop is 6.20 m/s, then the radius of the largest circle through which this pail could move without the water leaving the bottom of the pail would be what?

m = 3.75 kg

v = 6.20 m/s

r = ?

I was thinking to use Fc = mv^2/r but I'm not given Fc. I'm not sure what formula I should use or how to go about solving this question. Any help would be greatly appreciated.
 
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Redjakk1 said:
at the top of the loop is 6.20 m/s,
Step 1 read the question. Step 2 is to reread the question for the information you need.
 
Bystander said:
Step 1 read the question. Step 2 is to reread the question for the information you need.
What do you mean?
 
It's stated all over the forum that you are going to have to do some of the work. If I quote a piece of your original post, that is what is called a "hint."
 
Well I sort of figured that. I'm not trying to get out of doing the work, I'm just not sure what formula I should use or how I should go about the question.
 
Does the question place you specifically on the Moon? Or Mars? Or elsewhere in the solar system? You may assume that you are on the Earth's surface.
 
So g = -9.81. Is Fc equal to Fg or something like that then ?
 
Makes a good place to start.
 
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