What Is the Maximum Speed in This Simple Harmonic Motion Problem?

AI Thread Summary
In the discussion about maximum speed in simple harmonic motion (SHM), a mass oscillates between two points 5 cm apart and completes 40 oscillations per minute. The calculated maximum speed is 0.44 m/s, but there is confusion regarding the correct answer. After reviewing the calculations, it is confirmed that the frequency and amplitude were correctly determined, leading to a maximum speed of approximately 0.105 m/s. The initial claim of 0.44 m/s appears to be based on an incorrect answer key. The calculations provided demonstrate the correct methodology for determining maximum speed in SHM.
koat
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A mass between 2 springs moves with shm.
it oscillates between 2 points 5cm apart and completes 40 oscillations in 1min
whats its max speed?

Please help i always get the wrong answer
The answer is 0.44 but why?
 
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koat said:
A mass between 2 springs moves with shm.
it oscillates between 2 points 5cm apart and completes 40 oscillations in 1min
whats its max speed?

Please help i always get the wrong answer
The answer is 0.44 but why?

Show your solution attempt. We can't tell what's going wrong if we don't see what you're doing.
 
2pi*40/60= 4/3 pi
f= 4/3pi*1/2= 2/3
vmax= 2pi*2/3*2.5*10^-2
but the answer is wrong :(
 
koat said:
2pi*40/60= 4/3 pi
f= 4/3pi*1/2= 2/3
vmax= 2pi*2/3*2.5*10^-2
but the answer is wrong :(

Actually, your answer is correct. Looks like the answer key is wrong :smile:

You've correctly calculated the frequency of the oscillations:

## A = 5 cm/2 ##

## f = 40 cycles/min ##

##\omega = \frac{40 cycles}{min} \times \frac{1\;min}{60\;sec} \times \frac{2 \pi \; rad}{cycle} = \frac{4}{3}\pi \frac{rad}{sec}##

## v = A \omega = \frac{10 \pi}{3}\frac{cm}{sec} = 0.105 m/s ##
 
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