What Is the Maximum Value of Dv f(1,2) and Its Corresponding Direction v?

[team31]

when u=-0.6i+0.8j, Du f(1,2)=? gradient f=(18,9)
I use unit vector dot (-0.6,0.8) dotted with the gradient f, which turns out to be -3.6
so here is the question. A: the maximum value of Dv f(1,2) is=?
B: this maximum occurs when v=(?,?)
I'm confued with the Dv thing. For my guess is that I should use (1,2) to creat a unit vector which is (1/sqrt5, 2/sqrt5), and use that unit vetor dotted with the gradient f, which gives me the maximum value of Dv f(1,2)
then i will find a vector that its dot product with ( 1/sqrt5, 2/sqrt5) is 0, and tha should be the direction of V which is the answer for part B

Am I doing this right? plaese help me out. I've been looking into my textbook but couldn't find the symbol Dv, they all used Du. Thank u

 

[benorin]

Directional Derivatives

Directional Derivatives

Directional derivatives of $f(x,y)$ are, for unit vectors \vec{u}, are defined by:

D_{\vec{u}}f(x,y) = \vec{u}\cdot \vec{\nabla}f (x,y)​

where \cdot denotes the dot product. To see when the maximum value of the directional derivatives occurs, consider the magnitude of the directional derivative, recalling that \left|\vec{u}\cdot\vec{v} \right| = \left|\vec{u}\right|\cdot \left|\vec{v} \right|\cos \theta where \theta is the acute angle between the vectors we have that

\left| D_{\vec{u}}f(x,y)\right| = \left| \vec{u}\cdot \vec{\nabla}f (x,y)\right| = \left| \vec{u}\right|\cdot\left| \vec{\nabla}f (x,y)\right|\cos \theta = 1\cdot\left| \vec{\nabla}f (x,y)\right|\cos \theta = \left| \vec{\nabla}f (x,y)\right|\cos \theta​

since \left| \vec{u}\right| =1 since \vec{u} is a unit vector; consider that the quantity \left| \vec{\nabla}f (x,y)\right|\cos \theta is maximized when \cos \theta =1, i.e. when \theta =0 namely when the vectors \vec{u} and \vec{\nabla}f (x,y) are paralell. This occurs if \vec{u} = \frac{\vec{\nabla}f (x,y)}{\left| \vec{\nabla}f (x,y)\right|} which is a unit vector parallel to \vec{\nabla}f (x,y). The maximum value is then

D_{\frac{\vec{\nabla}f (x,y)}{\left| \vec{\nabla}f (x,y)\right|}}f(x,y) = \frac{\vec{\nabla}f (x,y)}{\left| \vec{\nabla}f (x,y)\right|}\cdot \vec{\nabla}f (x,y) = \frac{\left| \vec{\nabla}f (x,y)\right|^{2}}{\left| \vec{\nabla}f (x,y)\right|} = \left| \vec{\nabla}f (x,y)\right|​