What is the Minimum Horizontal Velocity for a Safe Dive from a 61m High Cliff?

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The minimum horizontal velocity required for a diver to safely clear the rocks from a 61m high cliff is calculated to be 6.52 m/s. This is determined by the equation 23 = Vx(t), where t is the time taken to fall, which is found to be 3.52 seconds. The vertical motion is analyzed with an initial vertical velocity of 0 m/s and an acceleration of -9.8 m/s², leading to a fall time of 3.52 seconds. The calculations confirm that both the horizontal and vertical components are correctly derived. Therefore, the diver must achieve a horizontal speed of at least 6.52 m/s to ensure safety during the dive.
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Please just check my answer.

Divers at Acapulco dive from a cliff that is 61m high. If the rocks below the cliff extend outward for 23m, what is the minimum horizontal velocity a diver must have to clear the rocks safely?

x problem

x=Vx(t)
23=Vx(t)
23=Vx(3.52)
23/3.52=Vx
Answer is Vx=6.52m/s

Y problem

Vy=0m/s
t=?
d=-61m
a=-9.8m/s/s

d=1/2a(txt)+Vi(t)

-61=-4.9(txt)
-61/-4.9=txt
12.44=txt
square root 12.44=txt Answer for Time is 3.52 Seconds
 
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All correct.
 
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