What is the minimum normal force he must exert?

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SUMMARY

The minimum normal force that the 50.0 kg climber must exert in a vertical chimney scenario is determined by the static friction forces acting on his shoes and back. With static coefficients of friction of 0.90 for the shoes and 0.65 for the back, the climber's weight (approximately 490 N) must be balanced by the maximum static friction forces. The net force must equal zero, leading to the conclusion that the normal force must compensate for the weight and the frictional forces exerted by both surfaces.

PREREQUISITES
  • Understanding of static friction and its coefficients
  • Basic knowledge of Newton's laws of motion
  • Familiarity with force equilibrium concepts
  • Ability to perform calculations involving mass, gravity, and friction
NEXT STEPS
  • Calculate the maximum static friction forces using the formula Ffr = µs * FN
  • Explore the implications of varying coefficients of friction in climbing scenarios
  • Study the effects of different angles and surfaces on normal force requirements
  • Learn about dynamic friction and its differences from static friction in climbing contexts
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Climbers, physics students, and anyone interested in understanding the mechanics of climbing and force equilibrium in vertical environments.

physicsss
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The 50.0 kg climber is supported in the "chimney" by the friction forces exerted on his shoes and back. The static coefficients of friction between his shoes and the wall, and between his back and the wall, are 0.90 and 0.65, respectively. What is the minimum normal force he must exert? Assume the walls are vertical and that the static friction forces are both at their maximum, Ffr = µsFN.
 
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physicsss said:
The 50.0 kg climber is supported in the "chimney" by the friction forces exerted on his shoes and back. The static coefficients of friction between his shoes and the wall, and between his back and the wall, are 0.90 and 0.65, respectively. What is the minimum normal force he must exert? Assume the walls are vertical and that the static friction forces are both at their maximum, Ffr = µsFN.

nice story, what exactly do you want?
 
So I know the net force must equal zero because the climber isn't moving.
I'm assuming the Ff can be determined by multiplying the mass*gravity*friction-coefficient.
But it seems that if Fnet=0, then the minimum Ff should just be equal to the climber's weight. (ie. Fg + Ff(1) + Ff(2) = 0 )

Hopefully I can get some help on this because it can't be that simple.
 

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