What is the minimum opening angle between two photons in a neutral pion decay?

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SUMMARY

The discussion centers on the decay of a neutral pion into two photons, focusing on calculating the minimum opening angle between the photons in the laboratory (LAB) frame. The decay involves relativistic effects, with the pion's momentum significantly exceeding its mass. The conservation of momentum and energy relationships, specifically E² = p²c² + (mc²)², are crucial for determining the angles of the emitted photons. By assuming equal angles for the two photons relative to the pion's motion, the minimum opening angle can be derived through symmetry considerations.

PREREQUISITES
  • Understanding of relativistic physics, particularly momentum and energy conservation.
  • Familiarity with the properties of neutral pions and their decay processes.
  • Knowledge of the energy-momentum relationship E² = p²c² + (mc²)².
  • Basic grasp of laboratory frame versus rest frame concepts in particle physics.
NEXT STEPS
  • Study the decay processes of other mesons, such as charged pions, to compare photon emission angles.
  • Learn about the implications of relativistic effects on particle decay and momentum distribution.
  • Explore advanced topics in particle physics, including Feynman diagrams for decay processes.
  • Investigate experimental methods for measuring photon angles in pion decay events.
USEFUL FOR

Particle physicists, students studying high-energy physics, and researchers interested in meson decay dynamics will benefit from this discussion.

schattenjaeger
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I forget the problem exactly but the general solution is good. I believe it was a neutral pion decaying into two photons

I don't know the numbers but I'm given momentum and it's gigantic, some GeV, opposed to the wussy pion mass so it's way relativistic

I could do the first part easy, it was like find out far the pion travels given its lifetime before decay(and then it gave me the lifetime)

However then it wanted the minimum opening angle between the two photons in the LAB frame. >_> I dunno, I figured I could assume both photons get half the pion's momentum, but then it seems like they should both be going in the same direction to conserve energy and momentum(although obviously I'm wrong)I know in the pion's rest frame to conserve momentum they both go out at 180 degrees apart(if they have half the momentum each I guess)but I don't know from there
 
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Can you do it assuming the angles are equal for the two photons from the line of motion of the pion? The energy momentum relationships E² = p²c² + (mc²)² and the conservation laws should get you the equal angle solution fairly easily. By symmetry, that has to be the minimum or maximum opening angle. It should not be too hard to show which it is.
 

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