What Is the Minimum Sample Size n for Pr[Yn≥0.99] to Be At Least 0.95?

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Homework Statement



Suppose that X1,...,Xn form a random sample from a inform distribution on the interval [0,1] and that the random variable Ynmax{X1,...,Xn}.
Determine the smallest value of n such that Pr[Yn≥.99]≥.95

Homework Equations



W=Yn-Y1 where W is the range of the sample
Y1=Z
Yn=W+Z
Y1=min{X1,...,Xn}


The Attempt at a Solution



f(x)= 1 for 0<x<1
F(x)=x for 0<x<1
h(w,z)=0 unless 0<w<1 and 0<z<1-w
G1(y)=Pr(1<y)= 1-Pr(Y1>y)= 1-[1-F(y)]n
=1-[1-x]
 
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Why are you considering the range? Your question concerns the maximum of the sample.

Two hints, using your notation of Y_n as the maximum value.
a) If Y_n \le y, you know that X_i \le y for i = 1, 2, \dots, n

b) The individual X_i values are independent

This should allow you to get the CDF of Y_n
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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