What is the negation of the statement

  • Thread starter Thread starter yxgao
  • Start date Start date
AI Thread Summary
The negation of the statement "For each s in R, there exists an r in R such that if f(r) > 0, then g(s) > 0" is "There exists an s in R such that for each r in R, f(r) > 0 and g(s) < 0." To find the negation of any logical statement, one can apply principles from Boolean logic, particularly focusing on contradictory statements. Key laws include the negation of universal and existential quantifiers, as well as the distribution of negation across logical operators. Understanding these principles allows for the effective transformation of statements into their negated forms. Mastery of these concepts is essential for logical reasoning and mathematical proofs.
yxgao
Messages
122
Reaction score
0
What is the negation of the statement "For each s in R, there exists an r in R such that if f(r) >0, then g(s) >0."

The answer is "There exists an s in R such that for each r in R, f(r) >0 and g(s) <0."

What is the general method to find the negation of any logical statement?

Thanks!
 
Physics news on Phys.org
Originally posted by yxgao
What is the general method to find the negation of any logical statement?
While I can't give you a general method, you may find it useful to review the concept of contradictory statements from Boolean logic:

All S is P is contradictory to Some S is not P

No S is P is contradictory to Some S is P

A statement and its contradictory cannot both be true (or both be false). Thus if "All S is P" is not true, then "Some S is not P" must be true. Of course, this only applies to statements that can be put in standard categorical form.
 
Basically, you just want to distribute the negation. Use the laws

\neg \forall x: P(x) = \exists x: \neg P(x)
\neg \exists x: P(x) = \forall x: \neg P(x)
\neg(x \wedge y) = \neg x \vee \neg y
\neg(x \vee y) = \neg x \wedge \neg y
\neg(x \Rightarrow y) = x \wedge \neg y
\neg(\neg x) = x
 
Last edited:
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'
Figure 1 Overall Structure Diagram Figure 2: Top view of the piston when it is cylindrical A circular opening is created at a height of 5 meters above the water surface. Inside this opening is a sleeve-type piston with a cross-sectional area of 1 square meter. The piston is pulled to the right at a constant speed. The pulling force is(Figure 2): F = ρshg = 1000 × 1 × 5 × 10 = 50,000 N. Figure 3: Modifying the structure to incorporate a fixed internal piston When I modify the piston...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top