What is the net force acting on the truck?

AI Thread Summary
The discussion focuses on calculating net forces acting on different systems. For the man on the air mattress, the upward force of water equals the downward gravitational force, resulting in a net force of zero, indicating he is neither sinking nor rising. In the case of the truck, the downward gravitational force and upward contact force balance each other at 48 kN, while the net horizontal forces consist of 4.5 kN east and 0.9 kN west, resulting in a net force of 3.6 kN east. Lastly, for vector a, its components can be analyzed using trigonometry to determine both magnitude and direction. Overall, the thread emphasizes the application of force balance and vector analysis in physics problems.
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1. A man is lazily floating on an air mattress in a swimming pool. If the weight of the man and air mattress together is 740 N, what is the upward force of the water acting on the system of man and mattress?




2. A truck driving on a level highway is acted upon by the following forces: a downward gravitational force of 48 kN (kiloNewtons); an upward contact force due to the road of 48 kN; another contact force due to the road of 4.5 kN, directed east; and a drag force due to air resistance of 0.9 kN, directed west. What is the net force acting on the truck?
and in what direction is it moving?





3.Vector a has components ax = - 2.9 m/s2 and ay = + 4.1 m/s2.

(a) What is the magnitude of vector a?
____ m/s2

(b) What is the direction of vector a?
____ ° CCW from the +y-axis
 
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Well for 1) you know the guy is floating. In other words, he's not sinking or rising, so the net force on him in the vertical axis is 0. You know the force of gravity on him, it's given. You know the net force is 0. Sooo you know _______ <--take a stab

2)Draw it and use trig

3)Same as above. It's one vector with magnitude 2.9 m/s^2 going left on the x axis, and one going 4.1 m/s^2 up. You can draw a right triangle and use trig
 
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