What is the net force on a door with multiple forces acting on it?

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SUMMARY

The net force on a door with multiple forces acting on it involves calculating the sum of forces and moments. In this scenario, two children apply forces of 50N each at distances of 0.05m and 0.07m, while a mother exerts a 100N force at 0.1m in the opposite direction. The correct equation for the sum of moments about the hinge is given by: (50N * 0.05m) + (50N * 0.07m * cos 35°) - (100N * 0.1m * cos 35°). The subtraction of the last term is justified as it represents a clockwise force opposing the counterclockwise forces.

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Homework Statement


A regular house door has 3 forces acting on it.At the moment the door is open by 35 deg. Let's say two children are pushing on a door and mum is on the other side pushing back
1/ at 0.05m is 50N acting directly perpendicular to the door
2/ at 0.07m is 50N acting at right angles to the door frame
3/ At 0.1m is an opposite direction force (clockwise[mum]from the other side of the door of 100n acting (as in case 2) perpendicular to the door frame or wall.


Homework Equations


What is the sum of forces??



The Attempt at a Solution

My attempt is as follows
Summation sign:?::: =(50N) (0.05m) + (50N) (0.07 cos 35Deg) - (100N) (0.1 cos 35Deg)

I am working of Moavini page 264.

I am essentially asking if my equation is correct in that i have SUBTRACTED the last force as it opposes the first two - am i right?? I subtract because the is clockwise not anti clockwise

Thanks ahead every body... keen engineering student... Peter
 
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Hi Peter welcome to the Forums!

Are you looking for sum of forces or sum of moments? If moments about the hinged size of the door, and your distances are measured from that side, then your answer for sum of moments looks good. Your subtraction of the last term is also correct. I don't have a copy of Moavani page 264 handy:smile:
 
Right thanks Phan, My teacher answered me to say that

Anti clockwise forces are given a negative notation and
Clockwise forces a positive notation. Although you can swap those values around, i think it is a good bookeeping exercise - as opposing forces are negative.

which is where i went wrong.

thanks ..Peter
 
Last edited:

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