What is the net torque given the angles of applied forces

AI Thread Summary
To calculate the net torque about a fixed point from two different forces, the formula Tnet = r1 X F1 + r2 X F2 is used, where r represents the distance from the pivot point to the point of force application. The direction of each torque must be considered, with counterclockwise torques being positive and clockwise torques negative. The net force is simply the sum of the two applied forces. To find the net torque, determine the direction of each force and apply the appropriate signs before summing. Understanding these principles allows for accurate torque calculations in physics problems.
tatiana
Messages
43
Reaction score
1
1. STATEMENT

Calculate the net torque about a fixed pointfor 2 different forces given the angles of the applied forces.

2. MY QUESTION

what is the net force, meaning how do i fint it? and what do i do wit the information given? Do i use T=r x F...
 
Physics news on Phys.org


tatiana said:
1. STATEMENT

Calculate the net torque about a fixed pointfor 2 different forces given the angles of the applied forces.

2. MY QUESTION

what is the net force, meaning how do i fint it? and what do i do wit the information given? Do i use T=r x F...
I think your question should have read, "..what is the net torque...?". In which case the net torque is the sum of the torques from each force , that is, Tnet = r1 X F1 + r2 X F2, where the direction of each torque (positive or negative) depends upon whether each torque is acting counterclockwise or clockwise about that fixed point.
 


The net force is simple the sum of the two forces. To determine the signs of the forces you must determine the direction the force is moving, either counterclockwise or clockwise. If clockwise the force is negative, and if counterclockwise the force is positive. Once you have determined the signs of the forces you simple add them together and you have your net torque.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanged mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top