What Is the New Electric Field When Charge and Distance Are Changed?

AI Thread Summary
When a point charge Q generates an electric field E at a distance R, doubling the charge to 2Q and measuring the field at a distance of 2R results in a new electric field value. The formula E = (k)(q/r^2) indicates that the electric field is inversely proportional to the square of the distance. Therefore, the new electric field at 2R with charge 2Q is calculated as E' = (k)(2Q)/(2R)^2, simplifying to E' = E/2. This confirms that the new electric field is indeed E/2. The relationship between charge, distance, and electric field strength is crucial for understanding electric fields.
kirby2
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An electric field of magnitude E is measured at a distance R from a point charge Q. If the charge is doubled to 2Q and the electric field is now measured at a distance of 2R from the charge, the new measured value of the field will be?

ATTEMPT: using the forumla E=(k)(q/r^2) i think the answer is E/2. is this right?
 
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kirby2 said:
An electric field of magnitude E is measured at a distance R from a point charge Q. If the charge is doubled to 2Q and the electric field is now measured at a distance of 2R from the charge, the new measured value of the field will be?

ATTEMPT: using the forumla E=(k)(q/r^2) i think the answer is E/2. is this right?

Looks good.
 
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