What is the Optimal Wire Spacing for a Strong Magnetic Field in a Solenoid?

AI Thread Summary
The discussion focuses on calculating the optimal wire spacing for a strong magnetic field in a solenoid using 12m of 0.50mm diameter copper wire. Participants clarify that "n," the number of turns per unit length, is crucial for determining how closely the wire can be packed. The correct calculation for n is derived from the wire's diameter, resulting in 2000 turns per meter. The limitations on the number of turns are primarily based on the wire's diameter rather than the overall length of the wire or the solenoid's dimensions. This understanding helps resolve the initial confusion regarding the calculation of n.
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Homework Statement



You have 12m of 0.50mm diameter copper wire and a power supply capable of passing 17A through the wire.
What magnetic field strength would you obtain inside a 2.0-mm-diameter solenoid with the wire spaced as closely as possible?

Homework Equations





The Attempt at a Solution


My problem is that I can't find n - tried about 50 times but its always wrong.
n=12/(pi*0.0205) wrong
n=12/(pi*0.02) wrong
n=0.02pi wrong never thought this was right but I can't think of anything else to do? for a mastering physics online question so no answer yet.
 
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I thought the only limitations were the length of the wire and the radius/diametre of the solenoid?
yeah n is turns/length
 
The turns per unit length tells you how closely you can pack the loops next to each other. The overall length of the wire and the size of the solenoid really have nothing to do with that.
 
really, so how do I find out n then?
 
hey, so n will be .0005/something
 
Almost! You have 0.0005 m per turn, so you have 1 turn per 0.0005 m, which is 2000 turns/m.
 
Thanks vela! that problem had me screwed.
 
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