What is the period of function f(x) = -sin(x/5 - pi)?

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The function f(x) = -sin(x/5 - pi) has a period of 10pi, derived from the standard period of the sine function, which is 2pi, divided by the coefficient of x, which is 1/5. The confusion around negative periods is clarified, as a period cannot be negative. A phase shift of -pi is present in the function, but it does not affect the calculation of the period. The correct approach involves determining the values of x that yield the same output for the function, confirming that the period is indeed 10pi. Understanding the relationship between the sine function's properties and the transformation applied is key to solving for the period.
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f(x) = - sin(x/5 - pi)

the period for this is -pi correct, since, k taken out it is 1, and by divide -pi into 1, the answer will be -pi only, correct??
 
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I don't think you can have a negative period!
To find the period pick a value of x (say zero) and then work out what is the next value of x that will give the same value of f().
Does adding the same constant to both values of X do anything?
 


Does it gives the same pi??
 


So, the answer is "pi"??
 


The period of sin() is pi ie sin(0)=sin(pi)

But in terms of X, since you divide X by 2 what value of X do you need for the function to give the same value as for x=0?
 


What is the exact period of f(x) (in radians)? (Recall p radians is equivalent to 180°; p is obtained by entering: Pi or pi.)

What does the question actually wants anyway?? how to calculate period in radians.
 


zero??
 


mgb_phys said:
The period of sin() is pi ie sin(0)=sin(pi)

This is not correct. A function f(x) is periodic with period p if
f(x+p)=f(x)
for all real x. For \sin(x), this is true for p=2\pi, and not true for p=\pi, because \sin(x+\pi)=-\sin(x), not \sin(x).
 


yes, and the answer is 10pi, by getting the 2pi divide 1/5 to get the answer. I get confuse that i need to multiply by 5 so to get b=5, but when i try 1/5, it's done.
 
  • #10


fr33pl4gu3 said:
yes, and the answer is 10pi

Correct!
 
  • #11


in this function, f(x) = - sin(x/5 - pi), the -pi would be a phase shift.

In general for sin (wt + q), w = 2pi f = 2 pi/T, where T is the period, and q is the phase shift.
 
  • #12


mgb_phys said:
The period of sin() is pi ie sin(0)=sin(pi)

But in terms of X, since you divide X by 2 what value of X do you need for the function to give the same value as for x=0?

No, the period of sin(x) is 2pi.

fr33pl4gu3. your function is -sin(x/5- pi). When x/5- pi= 0, what is x? When x/5- pi= 2pi, what is x? The difference between those is the period.
 
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