What is the Potential Energy of a Spring Between Two Masses?

AI Thread Summary
The potential energy of a spring between two masses can be expressed as PE = (1/2)*k*(d - p)^2, where d is the distance between the masses and p is the relaxed length of the spring. Initial calculations suggested separate horizontal and vertical potential energies, but the overall formula simplifies to the distance-based expression. The discussion emphasizes focusing on the distance between the masses rather than individual coordinates. This approach streamlines the understanding of the spring's potential energy in relation to its relaxed state.
rakshit1992
Messages
3
Reaction score
0
Member advised to use the homework template for posts in the homework sections of PF.
A planar object comprises of two masses joined by a linear spring with relaxed length p. The horizontal and the vertical displacements of the two masses are measured relative to a fixed point of reference as shown in the figure. What would be the potential energy of the spring?

My initial guess for this problem are that the spring will have a horizontal PE=(1/2)*k*(z-x)^2 and a vertical PE=(1/2)*k*(w-y)^2.

But something tells me that there might be the possibility of the PE=(1/2)*k*(sqrt(z^2+w^2)-p)^2-(1/2)*k*(sqrt(x^2+y^2)-p)^2.

Please help
 

Attachments

  • Untitled.jpg
    Untitled.jpg
    2.9 KB · Views: 366
Physics news on Phys.org
Forget the x and y coordinates for the moment. If the distance between the masses is d, how would you express the PE in terms of d and the relaxed length p?
 
In that case, I would assume it to be (1/2)*K*(d-p)^2
 
rakshit1992 said:
In that case, I would assume it to be (1/2)*K*(d-p)^2
OK. Express this in terms of the given quantities.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top