What is the power output of the sun?

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To find the power output of the sun, use the equation E = mc^2 to convert the mass of matter being converted into energy each second. Given that approximately 4 x 10^9 kg of matter is transformed, the power can be calculated as P = ΔE/Δt, where ΔE is the energy produced per second. Substituting the values, with c being 3.00 x 10^8 m/s, results in a power output of 3.6 x 10^26 W. The discussion highlights the simplicity of the calculation while illustrating the immense scale of energy conversion in the sun. Understanding this process emphasizes the vastness of solar energy production.
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I have a physics problem that I am stuck on: Approximately 4 x 10^9 kg of matter is converted into energy each second in the sun. Find the power output of the sun. I know the answer is 3.6 x 10^26 W I just can't figure out how to get the correct equation and numbers. Any help would be appreciated. Thanks
 
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The relevant equation is
E = mc^2
 
fishboy39 said:
I have a physics problem that I am stuck on: Approximately 4 x 10^9 kg of matter is converted into energy each second in the sun. Find the power output of the sun. I know the answer is 3.6 x 10^26 W I just can't figure out how to get the correct equation and numbers. Any help would be appreciated. Thanks

Use [ tex ] E = mc^2 [ /tex] to convert the mass to energy, then power is just energy per unit time.
 
Thanks! I knew it was something easy!
 
...why not e=mc^2?
 
LOL sorry must've left the window on too long... haha
 
e=mc^2
P=\frac{\Delta e}{\Delta t}=\frac{\Delta mc^2}{\Delta t}
Given \frac{\Delta m}{\Delta t}= 4*10^9 kg/s
c=3.00*10^8 m/s
 
This reminds me of a lecture my (lively) optics professor gave.
He asked us to just imagine four billion kilograms of matter being
converted every second.
"Suppose you would throw 700 g brick up into outer space every second. (he freely demonstrates what it would be like).
Now imagine all the people in the world doing that." It's amazing :bugeye:
 
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