What is the pressure in the middle of a vortex?

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In the center of a vortex, the pressure is calculated to be negative infinity, indicating an extreme drop in pressure relative to the surroundings. This occurs because the velocity of the fluid increases as it approaches the center, leading to a significant reduction in pressure according to Bernoulli's principle. The negative sign reflects the direction of the force acting on the area, which is determined by the chosen reference point. The external pressure counteracts the outward force on the swirling air, providing the necessary centripetal force to maintain the vortex. Thus, while the vortex pressure can reach zero, it cannot drop below this threshold.
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Homework Statement


The expression below describes a potential vortex in polar coordinates. What is the pressure p in the middle of the vortex, i.e. at radius r=0, relative to the surroundings?
##V_{\theta}=\frac{a}{r}##

Answer:
##p=-∞##


Does anyone have any explanation to this answer? Why is the pressure infinite? And why is it a negative? I've been thinking about this for so long and can't come up with any explanation...
 
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PhyIsOhSoHard said:

Homework Statement


The expression below describes a potential vortex in polar coordinates. What is the pressure p in the middle of the vortex, i.e. at radius r=0, relative to the surroundings?
##V_{\theta}=\frac{a}{r}##

Answer:
##p=-∞##Does anyone have any explanation to this answer? Why is the pressure infinite? And why is it a negative? I've been thinking about this for so long and can't come up with any explanation...
The minimum force per unit area is 0. The - or + sign simply denotes the direction in which the force acts on a unit of area which depends on which direction you choose to be +.

In a vortex, the swirling mass of air is kept from flying outward by the external pressure. So the difference between the vortex pressure and the external pressure supplies the centripetal force that the swirling molecules need in order to keep from flying outward. If the molecules swirl fast enough for a given radius of curvature, the centripetal force can be equal to the external pressure (atmospheric pressure) and the vortex pressure is then 0. It cannot go any lower than that.

AM
 
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