What is the Pressure on the Circular Side of a Cylindrical Drum of Molasses?

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To determine the pressure on the circular side of a cylindrical drum of molasses that is 25% full, the relevant formula is pressure equals weight density multiplied by depth. The total volume of the drum is calculated as 9pi ft^3, while the volume of molasses is 2.25pi ft^3. The challenge lies in accurately finding the depth of the molasses at the circular end of the drum, as pressure varies with depth. Additionally, integrating the pressure over the area covered by the molasses may be necessary to find the total force on the drum's lid. Understanding whether the problem seeks average or maximum pressure is crucial for an accurate solution.
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Homework Statement


A cylindrical drum of molasses is 25% full and laying on its side. The dimension sof the drum are 4 ft. height and 1.5 ft. radius. Find the pressure on the circular side (end) of the drum) created by the molasses.

Weight density of molasses = 100 lb/ft^3


Homework Equations


pressure = weight density x depth


The Attempt at a Solution


Total volume of drum = 9pi ft^3
Volume of molasses = 2.25pi ft^3

Thank you!
 
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I wonder if the makers of this problem really want the pressure, or if they want the maximum pressure, or the force on the lid of the drum. The pressure is not constant.
To find the pressure you have to calculate weight density x depth. Finding the depth
will be the tricky part.
If you want to calculate the force, you have to integrate the pressure over the part of the side that's covered in molasses.
 
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