What Is the Purpose of the Time Interval in Calculating Instantaneous Velocity?

AI Thread Summary
The discussion centers on calculating instantaneous velocity using the position function x(t) = (4.4 m/s) t + (0.91 m/s^3) t^3. Participants express confusion about determining the values of delta x and delta t, which are essential for calculating velocity. The time interval of 0.2 seconds is crucial for approximating instantaneous velocity, as it helps define the change in position over a specified time. To find delta x, participants need to evaluate the position at t = 2.6 s and at t = 2.4 s (2.6 s - 0.2 s). Understanding the purpose of the time interval is key to accurately computing the instantaneous velocity.
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A race car moves such that its position fits the relationship
x(t) = (4.4 m/s) t + (0.91 m/s^3) t^3 (yes cubed)
where x is measured in meters and t in seconds.Approximate the instantaneous velocity at t = 2.6 s, using a time interval of 0.2 s. Answer
in units of m/s.

i am just stuck and don't even know where to start
 
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ok, the velocity is
\frac{\Delta x} {\Delta t}

now the question come down to what is delta x and delta t
hope you can come out the answer
 
Take the time origin t_{0} to be 0.

Daniel.
 
but what is Xo and X?
 
Kay.
x_{0}=x(t_{0})=x(0)

x=x(2.6)

Daniel.
 
ok i got all that, but what is still confusing me is the "time interval" what do i do with that
 
dextercioby said:
Kay.
x_{0}=x(t_{0})=x(0)

x=x(2.6)

Daniel.


what is the time interval for?
 
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