What is the Radius of Curvature of the Outer Surface of a Contact Lens?

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The discussion revolves around calculating the radius of curvature of the outer surface of a contact lens with a given focal length and inner surface radius. The lens has an index of refraction of 1.58 and a focal length of +26.0 cm, with the inner radius of curvature specified as +20.0 mm. The thin lens equation is applied, leading to confusion regarding sign conventions for the radii. After some attempts and clarification on the positive signs for both radii, the correct outer radius of curvature is determined to be 1.768 cm. The solution is shared for the benefit of others facing similar problems.
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[SOLVED] Contact Lenses Problem

Homework Statement



A contact lens is made of plastic with an index of refraction of 1.58. The lens has a focal length of +26.0 cm, and its inner surface has a radius of curvature of +20.0 mm. What is the radius of curvature of the outer surface?

Homework Equations



The "thin lens equation"
1/f = (n-1)(1/R1 - 1/R2)

The Attempt at a Solution



This seems like a basic, out-of-the-book problem at first glance, but I can't get it. I've tried it several times, solving for R1 and R2 because I don't know which radius of curvature the 20.0 mm is. I think my main problems are probably sign errors and where to put the 20.0 mm (I don't know the rules for sign conventions in lenses, etc). Could someone point me in the right direction? Thanks.
 
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Nevermind, I figured out my answer; I might as well post the solution here for reference for others!

1/f = (n-1)(1/R1 - 1/R2)
(In this case, both R's should be positive.)
0.038 = (0.58)(1/R1 - 1/2)
0.038 = (0.58/R1) - 0.29
(Solve for R1)
R1 = 1.768 cm
 
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