What is the relationship between motor torque and force applied by a robot arm?

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The relationship between motor torque and the force applied by a robot arm is defined by the equation F = T/d, where F is the force, T is the torque, and d is the distance from the motor to the point of contact. The angle of the arm affects the torque due to gravitational forces acting on the robot's weight. For instance, if a robot weighs 10kg with an arm length of 0.2m, the maximum gravitational torque opposing the motors would be 19.62Nm. To successfully lift the robot, the combined torque from the motors must exceed this gravitational torque. Understanding these dynamics is crucial for effective robot arm design and operation.
ChristianMay21
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Background: I'm a high school robotics team member.

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These first two images show the general design of the robot; the design is intended to use two arms, with "hooks" on the end (more like a bearing on a shaft, really), represented by cylinders, to hook onto a steel bar, and pull itself up, using the force from the motors.

This is shown by these images.

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After the arms start pushing on the bar, the robot should begin to lift itself. The question is, given a motor on the joint with known torque, what is the force applied to the bar/weight that one can lift? Does it change with degrees? I'm familiar with physical terms so don't worry about dumbing it down. I just really really need an equation to relate these two XD The ones I've used seem to imply that the arm will exert zero force at some angles, which wouldn't make sense. Distance of the arm is known, also.

Thank you so much for your help!
 
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Hi,

The force that the arms would exert is equal to to the torque of the motor divided by the distance from the motor to the point of contact (F=T/d)

Depending on the angle (anything that isn't verticle), the torque would be effected by gravity. For example if the robot weighed 10kg and had an arm length of 0.2m, the maximum gravitational torque working against the motors would be 19.62Nm (gravity*weight*distance). To overcome this you would need a combined torque from the motors greater than this value.
 
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