What Is the Relative Velocity of Two Colliding Planets?

AI Thread Summary
The discussion focuses on calculating the relative velocity of two colliding planets using gravitational principles. Given their masses and radii, the gravitational force is expressed through the equation F=GMm/r^2. The initial kinetic and potential energies are set to derive the final velocity, yielding a result of 475.54 m/s. However, the calculation must consider the center of mass frame to ensure zero net momentum, indicating that the planets will not have equal velocities. The need for a more accurate approach to account for the differing masses and their respective velocities is emphasized.
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Homework Statement



Given: G = 6.67259 × 10^−11 Nm2/kg2
Two hypothetical planets of masses 2.5 × 10^23 kg and 7.8×10^23 kg and radii 3.2×10^6 m
and 7.1×10^6 m, respectively, are at rest when
they are an infinite distance apart. Because
of their gravitational attraction, they head
toward each other on a collision course.

When their center-to-center separation is
4.5 × 10^8 m, find their relative velocity. An-
swer in units of m/s.

Homework Equations


The Attempt at a Solution



F=GMm/r^2
M=7.8e23 kg
m=2.5e23 kg
Ki+Ui=Kf+Uf
r=4.5e8+3.2e6 +7.1e6=460300000m
0+0=.5mv^2+(-GMm/r)
.5v^2=GM/r
v=475.54 m/sIs this answer correct?
 
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I just tried to take the velocity from above and added the following:
v=at
475.54=at
F=ma
F=GMm/r^2
a=F/m
475.54/a=t

then I took the t value and tried to solve the velocity for the M mass. Then I found the difference between the two velocities. However, this is not right...any help is greatly appreciated!
 
In the frame where the origin is the center of mass of the two planets (which is where you should be working), the two planets don't move with equal velocity. They have to have 0 net momentum as well. m*v=M*V.
 
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