What is the repulsive force pushing these two spheres apart?

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The discussion focuses on calculating the repulsive force between two spheres formed during the fission of a uranium-235 nucleus. The spheres each contain 46 protons and have a radius of 5.9x10^-15m. The relevant formula for this calculation is Coulomb's Law, F = k(q1)(q2)/d^2, where k is Coulomb's constant. Participants clarify that the charges of the spheres, derived from the number of protons, should be used in the equation. The conversation emphasizes the importance of correctly identifying the variables needed for the calculation.
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Homework Statement



At the point of fission, a nucleus of 235U with 92 protons is divided into two smaller spheres, each with 46 protons and a radius of 5.9x10^-15m. What is the repulsive force pushing these two spheres apart?

Homework Equations



F = k(qi)(q2)/d^2

The Attempt at a Solution



I'm not quite sure what to use for the numerator of the equation. I believe that 5.9x10^-15m would be used as the distance. So, part of the equation would be (9*10^9)(x)(x)/5.9x10^-15.

Can anyone lead me to what numbers I SHOULD be using or at least give me a hint? Thank you! :)
 
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for coulomb's Law you consider the charges, not the masses...
 
Ah, sorry ._. I was looking over a different page in my notebook.
 

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