What is the resistance of a wire if its diameter is doubled?

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Doubling the diameter of a wire while keeping its volume constant results in a decrease in resistance by a factor of 16, as indicated by the Cambridge IGCSE exam answer key. This is derived from the relationship between resistance, length, and cross-sectional area, where resistance is inversely proportional to the area and directly proportional to the length. When the diameter increases, the cross-sectional area increases significantly, while the length must decrease to maintain constant volume. The confusion arises from the assumption about how these changes affect resistance, particularly in DC versus AC contexts. Understanding these principles clarifies why the resistance changes by such a large factor.
Kevin J
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This was a MCQ question on one of my Cambridge IGCSE Exams, the answer key said that the resistance would decrease by 16 folds (1/16 less then the previous one), I don't know how they got 16 from? (Apparently, I answered 1/4 and it was wrong)
 
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Your question doesn't sound like homework. But why did you say 4? Are you thinking DC or AC?
 
If DC resistance is directly proportional to crossectional area, then 1/4 sounds right.
πR∧2 VERS. π(2R)∧2 (Assuming the length is constant.)
 
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Here's the question, the mark scheme says it's D, how do you get D?
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What happens to the length?
 
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Likes jim hardy and Bystander
Chestermiller said:
What happens to the length?
It doesn't say anything, it was a question from CAMBRIDGE IGCSE
 
It says the new cylinder is the same volume as the old one.
 
ChemAir said:
It says the new cylinder is the same volume as the old one.
I have a feeling that the length decreases right?
 
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The volume of a cylinder is $$V=\pi\frac{D^2}{4}L$$If D doubles and V remains constant what does L have to do?
 
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Kevin J said:
Here's the question, the mark scheme says it's D, how do you get D? View attachment 233716
Kevin J said:
It doesn't say anything, it was a question from CAMBRIDGE IGCSE
Kevin J said:
I have a feeling that the length decreases right?
I does in fact mention the length. It states the volume of the putty remains constant as the diameter is increased by twice. For that to be true, the length must also change. Remember that resistance is approximated from resistivity and is inversely proportional to the cross-sectional area of the putty while also being proportional to the putty's length. If the length of the putty decreases while the area increases, the resistance will decrease by the seemingly "too large" factor shown above. Hope this helps.

The easiest way to handle these problems is to substitute in for some numbers and see what happens when you change the parameters.
 
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