What is the role of the cell in an electrolytic cell?

  • Thread starter Thread starter On_Pu
  • Start date Start date
  • Tags Tags
    Cell
AI Thread Summary
In an electrolytic cell, the attached cell, typically a battery, drives the electrolysis process by supplying electrons at one electrode and accepting them at the other, enabling non-spontaneous reactions. This setup creates polarity on the electrodes, attracting ions in the solution for oxidation and reduction. The efficiency of the electrolytic cell is calculated based on the charge used versus the charge passed, highlighting the role of the external cell in facilitating the reaction. For example, during the electrolysis of water, the battery facilitates the decomposition into hydrogen and oxygen gases through specific reduction and oxidation reactions. Understanding this interaction is crucial for grasping the overall function of electrolytic cells in electrochemistry.
On_Pu
Messages
1
Reaction score
0
While I was reading my notes on Electrochemistry, I found a cell attached to the main circuit in an electrolytic cell which perform electrolysis. What does this cell do there ? Does it create polarity on the platinum electrodes to attract the ions in the solution for oxidation or reduction or does it actually participate in electrolysis by supplying electrons. If the former is the case, then why do we write EFFICIENCY OF AN ELECTROLYTIC CELL = ( Charge Used) / ( Charged passed ) because only external cell has the capability to pass charges through the circuit.

I mean what does the cell do there... ?
 
Physics news on Phys.org
The battery drives the electrolytic cell by forcing the decomposition reaction: it supplies electrons at one electrode, and accepts an equal number at the other. The battery supplies the energy to cause a reaction which would not occur spontaneously.

For example, consider the electrolytic decomposition of water into H2 and O2 gases.
Cathode (reduction): 2 H2O(l) + 2e− → H2(g) + 2 OH−(aq)
Anode (oxidation): 4 OH−(aq) → O2(g) + 2 H2O(l) + 4 e−

For more details, http://www.chem.uiuc.edu/clcwebsite/elec.html
or search google or youtube.
 
Last edited by a moderator:
Back
Top