What Is the Second Force Acting on a Mass in the x-y Plane?

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To find the second force acting on a 1.5 kg mass accelerating at 7.3 m/s² at a 30-degree angle, the net force must first be calculated using Newton's second law, yielding a resultant force of 10.95 N. Given one force of 6.8 N in the positive x direction, the other force can be determined by vector addition. The problem requires using trigonometric functions to resolve the components of the second force. By applying these principles, the components of the second force can be expressed as a pair of values. Understanding vector addition and trigonometry is crucial for solving this problem effectively.
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Two forces, both in the x-y plane, act on a 1.5 kg mass that accelerates at 7.3 m/s^2 in a direction 30 degrees counterclockwise from the x axis. One force has magnitude 6.8 N and points in the + x direction. Find the other force. Express it as a comma separated pair of components.

I know this seems easy but I'm just not getting it. Any help?
 
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You know mass and acceleration so you can find the resultant net force's magnitude

You know one component of the resultant force is just a vector of magnitude 6.8N at 0 degrees(on the x-axis)

So that vector + another vector you need to find = the resultant vector

You should know equations for deducing both the magnitude and angle of the second vector(they involve trig and right triangles), then you can use trig to get those components.
 
if it involves trig then of course it involves right angles
 
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