What is the Significance of Testing Population Variance in a Sample?

gxc9800
Messages
18
Reaction score
0

Homework Statement


Given that 8 person vote for Mr Tan , i can't understand why the probability is sum of 0 people vote for him until 8 people vote for him. Why not the probability = 22c8 ( (0.6)^8 )( (0.4)^14) ?

Homework Equations

The Attempt at a Solution

 

Attachments

  • IMG_20141007_130758[1].jpg
    IMG_20141007_130758[1].jpg
    51.5 KB · Views: 473
Physics news on Phys.org
gxc9800 said:
Why not the probability = 22c8 ( (0.6)^8 )( (0.4)^14) ?
The probability ##22c8 ( (0.6)^8 )( (0.4)^14)## is the likelihood of drawing exactly this sample assuming the claim is true. When testing the hypothesis, you are comparing the cumulative probability of this sample (at least 8 people), against the claim.
Note that the expected value, assuming his claim is true would be ##22(.6)=13.2## people. If you just take the probability of 13 people saying they support him, that will not be 50%, but the cumulative probability will be close to that.
 
hi, When testing the hypothesis, you are comparing the cumulative probability of this sample (at least 8 people), against the claim

why the author doesn't say 'the investigator selects a random smaple of 22 people and at most 8 people agree to vote for him ' instead?
 
The question is: How likely is it to find something at least as extreme as what was observed? That is normally what people mean when they talk about p-values and significance. It is not: What is the probability of pulling this sample assuming that H0 is true?
The author may not state it, but that is what is always meant by testing significance.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top