What is the solution to (x-7)^2=(x+3)^2?

AI Thread Summary
The equation (x-7)^2=(x+3)^2 can be solved by recognizing that squaring both sides does not directly imply the variables are equal. Instead, the correct approach involves expanding both sides to obtain x-7=x+3. This leads to the realization that the variables cancel out, indicating no solution if treated incorrectly. The proper method involves understanding that if a^2 = b^2, then a = ±b, which applies to this equation. Thus, the solution is found to be x = 2.
mistalopez
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Homework Statement



(x-7)^2=(x+3)^2

2. The attempt at a solution

I squared both sides and received x-7=x+3

However, that cannot be correct because the variables cancel out which means there is no solution. The book shows that there is a solution of 2
 
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hi, instead of squaring both sides, try multiplying them out as you know (x-7)^2 is the same as (x-7)(x-7) ..
 
mistalopez said:
I squared both sides
You mean you took the square root of both sides?

Well, there's a problem: the phrase
a2 is the square of b​
is not synonymous with
a is b​

So you cannot infer that the two square roots are equal...
 
Supplementing what Hurkyl said, if a2 = b2, then a = +/b. You can apply this principle to your equation.
 
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