What is the Specific Heat Capacity of the Unknown Material?

AI Thread Summary
To find the specific heat capacity of an unknown material, a 50g sample heated to 80 degrees Celsius is placed in a calorimeter with 100g of water at 10 degrees Celsius, raising the water's temperature by 5 degrees. The heat capacity of the calorimeter is 20 J/K. The equation MC delta T = MC delta T can be applied, but the user is unsure how to determine the heat (Q). The final temperature of the unknown material equals that of the water. The discussion emphasizes the need to clarify the value of Q in the calculations.
noobatphysics
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Homework Statement


In order to find the specific heat capacity of an unknown material,
a 50g piece is heated to 80 degrees Celsius and fully immersed in a well
insulatyed calorimeter filled with 100g of water at 10 degrees Celsius raising the temperature of the water by 5 degrees, the heat capacity of the calorimeter is 20 J K-1


Homework Equations


MC delta T = MC delta T ?




The Attempt at a Solution


no idea to be honest
at first i thought i can just use Q=mc delta T to do this but i don't know what Q is :S
 
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The final temperature of substance is same as that of water. You could still use the eqn. you wrote.
 
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