What is the speed of an object falling from a rotating spherical shell setup?

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The problem involves calculating the speed of a mass m = 0.60 kg falling from a uniform spherical shell with mass M = 4.5 kg and radius R = 8.5 cm, which rotates around a vertical axis. The system includes a pulley with rotational inertia I = 3.0 x 10-3 kg m2 and radius r = 5.0 cm. Using energy conservation principles, the gravitational potential energy lost by the falling mass is converted into both the rotational kinetic energy of the shell and the linear kinetic energy of the falling mass. The final speed of the object after falling 82 cm can be determined through these energy considerations.

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ekram
moved from general forum so homework template is missing
Hello everyone,

I am having trouble finding the solution to this problem shown below:-
  1. A uniform spherical shell of mass M = 4,5kg and radius R = 8,5cm can rotate around a vertical axis on frictionless bearings. A massless cord passes around the equator of the shell over a pulley of rotational inertia I = 3,0 10- 3kg m2 and radius r = 5,0cm, and is attached to a small object of mass m = 0,60kg. There is no friction on the pulley’s axel; the cord does not slip on the pulley. What is the speed of the object when it has fallen 82cm after being released from rest? Use energy considerations.
can anyone kindly guide me to the solution to this problem.
 
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Consider the changes in the following;
-Gravitational potential energy
-Rotational kinetic energy
-Linear kinetic energy
 

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