What is the speed of M2 at t=1.75 s in a system of three blocks and two pulleys?

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The discussion focuses on calculating the speed of block M2 at t=1.75 seconds in a system with three blocks and two pulleys, where M1, M2, and M3 have masses of 3.0 kg, 9.0 kg, and 5.0 kg, respectively. Participants emphasize the need to account for different tensions in the system and derive equations for each mass to solve for acceleration and velocity. The correct approach involves setting up equations based on forces acting on each block and solving for the acceleration, which is found to be approximately 1.4 m/s². After determining acceleration, the velocity of M2 can be calculated using the formula v = vo + at, leading to a successful resolution of the problem. The discussion concludes with a participant confirming their calculations after correcting their approach.
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Homework Statement


three blocks are relased at t=0 from the position shown in the figure. Assume that there is no friction between the table and M2, and that the two pulleys are massless and frictionless. The masses are: M1 = 3.0 kg, M2 = 9.0 kg, M3 = 5.0 kg.

M2 is the middle block connected to M1 (to the left) and M3 (to the right)

Calculate the speed of M2 at a time 1.75 s after the system is released from rest.


Homework Equations


Since they will all have the same acceleration, i was trying to look for a and then multiply that by the t.



The Attempt at a Solution



I set up this equation:
FM1 = Tension - M1*g = M1a
FM3 = Tension - M3*g = (M1 + M2 + M3)a

and i get a to be 1.4m/s^2 and Vf to be 2.45m/s but it is incorrect. Any help pls?
 
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Tension in the two strings are not the same.
Note down which mass goes up and which mass goes sown.
Accordingly write down three equations for three masses.
You have three unknowns, T1, T2 and a. Solve for them.
 
wait, how are the two tensions different though?
I know that FM1 = Tension - M1*g = M1a is correct, so is tension for Fm3 going to be (m1+m2)a?
 
M3*g - T1 = M3*a ...(1)
T1 - T2 = M2*a...(2)
T1 - M1*g = M1*a ...(3)
Solve for a.
 
if i found a, how do i find the speed of m2?
 
leavex said:
if i found a, how do i find the speed of m2?

Use v = vo + at. vo is zero.
 
i tried it doesn't work, i have the same question but but different m
m1=2 m2=8 m3=4
i get zero for answer and its wrong... i did exactly the same way you did above...
 
leavex said:
i tried it doesn't work, i have the same question but but different m
m1=2 m2=8 m3=4
i get zero for answer and its wrong... i did exactly the same way you did above...

What is your value of a?
 
i solved id and got 0 for a
m3g-m1g-m1g=4-2-2=0
 
  • #10
4g - T2 = 4a...(1)
T2 - T1 = 8a...(2)
T1 - 2g = 2a...(3)

From these equations find a.
 
  • #11
i did it doesn't wark i just don't know what do i do wrong...
i got a=1.962
t= 1.45
v=2.84 m/s
why is it wrong??
 
  • #12
If you add (1) and (3), you get

T1 - T2 + 2g = 6a.

2g = 6a + T2 - T1 = 6a + 8a = 14a.

So a = 2g/14 = 2 * 9.8/14 = 1.4 m/s^2

Now find the velocity of m2.
 
  • #13
yeahhhhhhhhhhh it fianely worked, thank you so mach!
 
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