What is the speed of the boat after time 2.00 hr has passed?

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The discussion centers on calculating the speed of a boat after 2 hours while it accumulates rainwater, with a focus on understanding the effects of drag force on momentum. The boat, initially moving at 3.00 m/s, has a mass of 250 kg and collects rain at a rate of 10.0 kg/hr. Participants seek clarification on the acceleration of the boat after rain begins, specifically in relation to the drag force, which is proportional to the square of the speed. There is confusion regarding the conservation of momentum in the presence of drag and whether to consider the drag force as analogous to a collision. The conversation emphasizes applying Newton's 2nd law to solve for acceleration and the implications of drag on momentum conservation.
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Can you please help me out with the second part of this question? I got the first two parts. Its PART C that I am not getting. Thanks!

A boat of mass 250 kg is coasting, with its engine in neutral, through the water at speed 3.00 m/s when it starts to rain. The rain is falling vertically, and it accumulates in the boat at the rate of 10.0 kg/hr.

Part A
What is the speed of the boat after time 2.00 hr has passed? Assume that the water resistance is negligible.

Part B
Now assume that the boat is subject to a drag force F_d due to water resistance. Is the component of the total momentum of the system parallel to the direction of motion still conserved?

Part C
The drag is proportional to the square of the speed of the boat, in the form F_{\rm d}= 0.5 v^2. What is the acceleration of the boat just after the rain starts? Take the positive x-axis along the direction of motion.
Express your answer in meters per second per second.


Its Part C that I am not getting. Please help. Thanks!


Thank-you very much for all your time and effort!
 
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Use Newton's 2nd law.
 


Is the component of the total momentum of the system parallel to the direction of motion still conserved?

I do not get part B, the part where the system is parallel to the direction of motion. can anyone explain??

do i think of the boat and the drag force as a collision? therefore, total momentum is conserved?
 
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