What is the spring constant in terms of mass and unstretched length?

AI Thread Summary
The discussion centers on determining the spring constant (k) for a mass attached to a spring that is swung in a circular motion. The mass does not follow a circular path due to the oscillation of the spring, resulting in an egg-shaped trajectory. Participants emphasize the need to express k in terms of known quantities such as mass (m) and unstretched length (L), rather than using undefined variables. The importance of analyzing forces at the top and bottom of the path, as well as applying conservation of energy principles, is highlighted for solving the problem. Ultimately, the correct formulation of the spring constant remains a key focus for clarification.
cosmo1993
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Homework Statement


A mass m is connected to a spring with unstretched length L. You hold on to one end of the spring and swing the mass around. You practice getting the mass going until the spring just goes slack at the top of the path. At the bottom of the path. the spring stretches by an amount equal to half of its unstretched length.
Why doesn't the mass make a circular path?
Find the spring constant k of the spring

Homework Equations


F = -kΔs
at the bottom of the circle
Normal force = mg + ma

The Attempt at a Solution


I figured that the mass does not make a circular path because the spring is oscillating as it travels around the circle, therefore, the path of the mass is more egg shaped.

I said that K = (m(g+a))/Δs would be the spring constant but I am not sure if I am correct. Any help?
 
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No, that's not correct. What's ##a##? What's ##\Delta s##? What about ##L##? You haven't expressed ##k## in terms of known quantities.

By the way, there is no normal force. A normal force is a force exerted by a surface in contact with an object. The mass isn't in contact with any surface, so there can be no normal force.

Start by drawing a free-body diagram for the mass at the top of the path and at the bottom of the path.
 
cosmo1993 said:

Homework Statement


A mass m is connected to a spring with unstretched length L. You hold on to one end of the spring and swing the mass around. You practice getting the mass going until the spring just goes slack at the top of the path. At the bottom of the path. the spring stretches by an amount equal to half of its unstretched length.
Why doesn't the mass make a circular path?
Find the spring constant k of the spring

Homework Equations


F = -kΔs
at the bottom of the circle
Normal force = mg + ma

The Attempt at a Solution


I figured that the mass does not make a circular path because the spring is oscillating as it travels around the circle, therefore, the path of the mass is more egg shaped.

I said that K = (m(g+a))/Δs would be the spring constant but I am not sure if I am correct. Any help?

You need to give the spring constant in terms of L and m. What is a and what is its direction?

You are right, the mass does not follow a circular path. What forces act on it at the highest and at the lowest points?

At these points, you can consider the path as piece of some circle. There must be some force pointing towards the centre to make the path. How those forces are related to the speed and the distance from the centre?

You can also assume conservation of energy.

ehild
 
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