What is the Static Equilibrium of a Pulley System?

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In a static equilibrium pulley system with a 0.5 kg mass on one side and a 2.0 kg mass on the other, the tension in the string and the normal force on the 2.0 kg box are key calculations. The system is frictionless and the string is massless, simplifying the analysis. To find the tension, one should start with the mass experiencing the least forces, which is the 0.5 kg mass. The normal force on the 2.0 kg box can be determined using the equation of motion, ensuring that the sum of forces equals zero. Understanding these principles is crucial for solving problems involving static equilibrium in pulley systems.
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Homework Statement



A system with a pulley, string, and mass has a string on a pulley holding 0.5 kg on one end and 2.0 kg on the other. It is in static equilibrium; the pulley is frictionless; the string is massless.
What is the tension in the string holding the pulley?
What is the value of the normal force on the 2.0 kg box?

Homework Equations



f=ma


The Attempt at a Solution



t-(2*9.8)=F? (part a)
 
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hi runningirl! :smile:
runningirl said:
A system with a pulley, string, and mass has a string on a pulley holding 0.5 kg on one end and 2.0 kg on the other. It is in static equilibrium; the pulley is frictionless; the string is massless.
What is the tension in the string holding the pulley?
What is the value of the normal force on the 2.0 kg box?
…
t-(2*9.8)=F? (part a)

is the 2.0 kg mass resting on the ground?

if so, always start with the mass with the least number of forces acting on it (because that's easiest! :biggrin:), and then work your way round to the others

in this case, that's the 0.5 kg mass …

so what is the ∑F = 0 equation for that? :smile:​
 

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