What Is the Tension in the String for a Pullstring Walker on a Slope?

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SUMMARY

The discussion focuses on calculating the tension in the string of a pullstring walker positioned on a slope with a 10-degree angle. The walker has a mass of 50 kg, and the user attempts to apply Newton's second law to derive the tension. The user correctly identifies that the hypotenuse of the triangle formed by the string is approximately 49.24 N, confirming that their calculations are now accurate compared to previous attempts.

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here is how the problem looks.

http://i39.tinypic.com/2d0j4wg.png


a pullstring walker is in the middle of a string that is connected to two mountain sides. the string formes an angle of 10 degrees under the horizontal. the walker has a mass of 50 KG. find the tension of the string

any idea how to start with this one.if i set up Newton 2nd law i get FG-FT+FT= 0
which is useless because FT will cancel out.
 
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when i do the geometry i get an unreasonable answer of

cosθ= adjacent/hyp
cos10= 50/ hyp
hyp=50/ cos10
hyp = 49.24 N.
is that correct?

i did it wrong last time. i believe this is correct. answer is reasonable this time!
 

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