What is the tension in the string needed to support the hanging box?

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The discussion revolves around calculating the tension in a string supporting two 10-kilogram boxes connected over a frictionless pulley. The tension was calculated to be 93.3 N, with the forces acting on the box on the inclined plane drawn and labeled. The frictional force acting on the box was determined to be 15 N for static friction and 13 N for kinetic friction. Additionally, the mechanical energy converted into thermal energy during the slide was calculated as 26 J, while the kinetic energy of the left-hand box upon reaching the bottom was found to be 173 J. Participants are encouraged to provide feedback and show their work for further guidance.
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Homework Statement


1985 B2


Two 10 kilogram boxes are connected by a massless string that passes over a massless frictionless pulley as shown above. The boxes remain at rest, with the one on the right hanging vertically and the one on the left 2.0 meters from the bottom of an inclined plane that makes an angle of 60° with the horizontal. The coefficients of kinetic friction and static friction between the Ieft hand box and the plane are 0.15 and 0.30, respectively. You may use g = 10 m/s2, sin 60° = 0.87, and cos 60° = 0.50.
[img=http://img140.imageshack.us/img140/287/physicsxb6.th.png]
a. What is the tension T in the string?


b. On the diagram below, draw and label all the forces acting on the box that is on the plane.

c. Determine the magnitude of the frictional force acting on the box on the plane.

The string is then cut and the left hand box slides down the inclined plane.

d. Determine the amount of mechanical energy that is converted into thermal energy during the slide to the bottom.

e. Determine the kinetic energy of the left hand box when it reaches the bottom of the plane.

The Attempt at a Solution



my answers:
a. T= 93.3N
b. I drew:
normal force = 100cos(60)
friction force = Fnormal x static friction coefficient
mg = 100N
Tention
[img=http://img441.imageshack.us/img441/9864/physics2tj3.th.png]
c. static Ffric = 15N ... KE Ffric = 13N
d. 26J
e. 173J

Feedbacks or corrections is appreciated but I think I got everything right =D I THINK!
 
Last edited:
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How did you get the value of T? What are the forces acting on the hanging block on the right?
 
um what did you get get your answer?
 
You are supposed to show your work, after which I may guide you.

Just answer me this: what should be the tension in the string to support the hanging box on the right?
 
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