What is the tension of the rope connecting two masses in Yellow Creek?

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The discussion revolves around calculating the tension in a rope connecting two fish, a carp and a trout, while being lifted with a force of 86.7 N. Participants analyze the forces acting on both fish, applying Newton's laws to set up equations for tension and weight. There is confusion regarding the correct application of forces, particularly how gravity affects the carp and trout. One participant suggests that the system may be lifted at a constant force, implying zero acceleration, which is debated. Ultimately, there is a consensus that the equations are correct, but discrepancies in the calculated tension indicate potential arithmetic errors that need to be resolved.
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Homework Statement



Jimmy has caught two fish in Yellow Creek. He has tied the line holding the 4.10 kg steelhead trout to the tail of the 1.45 kg carp. To show the fish to a friend, he lifts upward on the carp with a force of 86.7 N. What is the tension of the rope connecting the steel trout and carp?

m1 = 1.45 kg
m2 = 4.1 kg

Homework Equations



F = ma
Basically Newton's three laws

The Attempt at a Solution



I'm not entirely sure if this is correct or not, but I had a hard time drawing the FBDs and wasn't sure where to really begin. For the carp, I came up with this:

m1a = 86.7 - m1g - m2g - T

and the trout:

m2a = T - m2g
 
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I don't think you even need to worry about the carp. If the carp is what is being held, it won't have an effect on the tension. However, your equation for the trout would then be incorrect. You have the tension and the upward force both in the positive direction and the force of gravity in the negative direction. I think you may have to assume that the system is being lifted up at a constant force, so the acceleration of the system would be zero.
 
Welcome to Physics Forums :smile:

sdiddy said:

The Attempt at a Solution



I'm not entirely sure if this is correct or not, but I had a hard time drawing the FBDs and wasn't sure where to really begin. For the carp, I came up with this:

m1a = 86.7 - m1g - m2g - T

and the trout:

m2a = T - m2g

This is pretty close, I see only one problem. Note that -m2g is the force due to gravity acting on the trout; it should not enter into the forces acting on the carp.

The downward "pull" on the carp, due to the trout, is expressed by the tension force -T.

w3390 said:
I think you may have to assume that the system is being lifted up at a constant force, so the acceleration of the system would be zero.
Compare the 86.7 N upward force with the combined weight of the two fish. Do you still think the acceleration is zero?
 
So what you are saying is:

m1a = 86.7 - m1g - T
m2a = T - m2g

Even then, when I solve for tension, I keep getting the wrong answer. The answer I keep getting is 14.7 N. I still don't know what I'm doing wrong.
 
Your equations are correct, but I am getting a different value for the tension. You probably have a simple arithmetic or algebra mistake somewhere.

Try again, and if the answer is still wrong then post your algebra work and we'll try to find just where the error is.
 
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