What is the tesion between the two masses?

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The discussion centers on calculating the tension between two connected masses (1kg and 2kg) being pulled by a force F. The total acceleration of the system is determined to be a = F/3. Participants analyze the forces acting on each mass using Newton's second law, leading to the conclusion that the tension in the string must be consistent for both masses. Ultimately, it is established that the tension T is equal to F/3, as both masses experience the same tension force due to the connection. The analysis confirms that the tension is the same regardless of which mass is examined.
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there are two masses connected by a string:

1kg-----2kg---->F

the 2 masses are being pulled by a force of F

what is the tesion between the two masses?

the total acceleration is a=F/3

this means that the tesion is either 2kg*F/3 or 1kg*F/3

not sure which one?
 
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UrbanXrisis said:
the total acceleration is a=F/3
Correct.

this means that the tesion is either 2kg*F/3 or 1kg*F/3

not sure which one?
Figure it out! Pick one of the masses and apply Newton's 2nd law. (You already know the acceleration.)
 
right, that's what I'm asking, do I apply it to the 1kg mass or the 2 kg mass?
 
You think Newton's 2nd law only works for one of them? :smile:

It better work for either mass. Now, of course, if you pick the correct mass to analyze the problem is easier.

Start by identifying the forces that act on each mass.
 
if I apply it to the 1 kg mass... it will be T=F/3

if I apply it to the 2 kg mass... it will be T=2F/3
 
Obviously that's not right since there is only one tension in the string.

How many forces act on the 1kg mass? How many forces act on the 2kg mass?
 
one force acts on the 1kg mass, 2 forces act on the 2kg mass

does that mean the tension force is only exerted on the 1kg mass?
 
You tell me. The string exerts its tension force on anything it's attached to.
 
oh, so only the 1 kg mass is effected, so that means the T=F/3
 
  • #10
Both masses are affected, but hte tension in the string generally results from a force applied on BOTH ends. In this problem, both ends have atleast a force of 1kg*F/3 on them, therefore that is the tension.
 
  • #11
Analyzing the 1 kg mass:
F_{net} = ma
T = (1)(F/3) = F/3

Analyzing the 2 kg mass:
F_{net} = ma
F - T = (2)(F/3) = (2/3)F ==> T = F/3
 
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