What is the Time-Evolved State of a Single-Mode Cavity Field?

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Homework Statement



Suppose the state of a single-mode cavity field is given at time t=0 by

<br /> |\Psi(0) \rangle = \frac{1}{\sqrt{2}}(|n \rangle + e^{i\phi}|n+1 \rangle)<br />

where phi is some phase. Find the state |\psi(t)\rangle at times t > 0.

Homework Equations



I'm a little confused of what to do with this one, I know that |n\rangle = \frac{(\hat a^{\dagger})^n}{\sqrt{n!}}|0\rangle and think I make have to substitue for the n eigenvalue using that somehow of that somehow and integrate.
 
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What equation determines the time evolution of any state in quantum mechanics?

Apply that equation!
 
The SE.

Just
<br /> |\Psi(t) \rangle = e^\frac{-iEt}{\hbar}|\Psi(0) \rangle = e^\frac{-iEt}{\hbar}\frac{1}{\sqrt{2}}(|n \rangle + e^{i\phi}|n+1 \rangle)<br /> ?
 
No...do the states |n> and |n+1> have the same energy?
 
<br /> |\Psi(t) \rangle = \frac{1}{\sqrt{2}}(e^\frac{-iE_{n}t}{\hbar}|n \rangle + e^\frac{-iE_{n+1}t}{\hbar}e^{i\phi}|n+1 \rangle)<br />
 
yeah...and what are the values of E_n and E_{n+1}?
 
E_n = \hbar \omega(n + 0.5)
E_{n+1} = \hbar \omega(n + 1.5)
 
Right, substitute that in your last equation, take a common phase factor out, done.
 
How does the common phase factor come out?
 
  • #10
That follows from \exp(i\phi) \exp(i\phi&#039;)=\exp(i(\phi+\phi&#039;))
 
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