What is the Transfer Function H(s) for the Given Circuit?

AI Thread Summary
The discussion focuses on finding the transfer function H(s) for a given circuit using the node voltage method. The user has set up the equation based on the circuit parameters, with C1 and C2 converted to their frequency domain equivalents. However, they encounter a problem with having two unknowns and only one equation. A suggestion is made to write an additional equation at the output node to resolve the issue. This approach aims to establish a system of two equations with two unknowns to solve for the transfer function.
sinned4789
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Homework Statement


find the transfer function H(s)
[PLAIN]http://img192.imageshack.us/img192/4204/asdwoe.jpg


Homework Equations


H(s) = Vout/Vin
done in the frequency domain so: C1 and C2 turns into 1/sC
where C1 = C2 = .1F
and R1 = R2 = 20


The Attempt at a Solution


to find the transfer function, i have to apply an impulse source. therefore, Vin is just 1V.
my attempt at this by using node voltage method:
(Vx is the node that connects R1, R2, and C2)

(Vx -1)/20 + Vx/(10/s) + (Vx - Vout)/20 = 0

i am stuck with two unknowns and 1 equation. :[
 
Last edited by a moderator:
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bump, anyone?
 
sinned4789 said:

Homework Statement


find the transfer function H(s)
[PLAIN]http://img192.imageshack.us/img192/4204/asdwoe.jpg


Homework Equations


H(s) = Vout/Vin
done in the frequency domain so: C1 and C2 turns into 1/sC
where C1 = C2 = .1F
and R1 = R2 = 20


The Attempt at a Solution


to find the transfer function, i have to apply an impulse source. therefore, Vin is just 1V.
my attempt at this by using node voltage method:
(Vx is the node that connects R1, R2, and C2)

(Vx -1)/20 + Vx/(10/s) + (Vx - Vout)/20 = 0

i am stuck with two unknowns and 1 equation. :[

Write another equation, then you'll have 2 equations and 2 unknowns. I would write one at the output node.
 
Last edited by a moderator:
The difference between the voltages of the output and input nodes is the voltage across C1 and also the sum of the voltages across R1 and R2.
 
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