What is the value of A in Ψ=Acos^2(x) for a particle's wave function?

AI Thread Summary
The discussion revolves around finding the normalization constant A in the wave function Ψ=Acos^2(x) for a particle defined in the interval -π/2 < x < π/2. A participant initially calculated A as zero, but the correct value is √(8/3π). Another user emphasizes the importance of showing work to identify where mistakes may have occurred. The mention of using π/4 instead of π/2 suggests a potential error in the integration limits. The conversation highlights the need for careful calculations in quantum mechanics problems.
Hamza Abbasi
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Homework Statement


The wave function of a certain particle is Ψ= A cos^2(x) for -π/2 < x < π/2. Find the value of A.

Homework Equations

The Attempt at a Solution


My answer is coming out to be zero wheres as the correct answer is under root 8/3π ... Please help me out !
 
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You're going to need to show your work, otherwise we have no idea where you've made a mistake.
 
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i have used pi/4 instead of pi/2 ignore that pls
 
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