What Is the Value of 'a' in the Infinite Geometric Series?

AI Thread Summary
The discussion centers on solving for the value of 'a' in the infinite geometric series 3 + 3a + 3a^2 + ... = 45/8, where a > 0. Participants clarify that the correct formula for an infinite geometric series is S = a / (1 - r), not the formula for a finite series. The series is identified as having infinite terms, prompting a focus on the behavior of r as n approaches infinity. The key insight is recognizing that for convergence, the common ratio r must satisfy -1 < r < 1. The conversation emphasizes the importance of using the right formula to find the solution.
lionel messi.
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Sequences and series help...

1. Homework Statement
3+3a+3a^2+...∞ is = to 45/8 where a>0,then a is...?


3. The Attempt at a Solution
since it is a g.p so using
S=(a(rn-1))/(r-1) for r>1
ive all the values except for "n"..can someone help...:/
 
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lionel messi. said:
S=(a(rn-1))/(r-1) for r>1
ive all the values except for "n"..can someone help...:/
Wrong formula. This is an infinite geometric series, so use
a + ar + ar^2 + ar^3 + ... = \frac{a}{1 - r}
 


thanks..
 


n is the number of terms, so in this case there are infinite terms.
As n tends to infinity, what does r^n tend to? (Assuming -1<r<1)
This gets you to the formula that eumyang posted.
 

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