What is the velocity of car 2 when car 1 is going 1/2 the speed of light?

ehrenfest
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car 2 is twice as long as car 1 when they are at rest

a stationary policeman observes that car 2 is the same length as car 1 as car 2 passes car 1 going through a speed trap.

car 1 is going 1/2 the speed of light

I tried to solve this with

L 1/sqrt(1-(1/2)^2) = 2L/sqrt(1-v^2/c^2) and I got an imaginary anwer
 
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ehrenfest said:
car 2 is twice as long as car 1 when they are at rest

a stationary policeman observes that car 2 is the same length as car 1 as car 2 passes car 1 going through a speed trap.

car 1 is going 1/2 the speed of light

I tried to solve this with

L 1/sqrt(1-(1/2)^2) = 2L/sqrt(1-v^2/c^2) and I got an imaginary anwer

your equation is wrong. the sqrt(1-v^2/c^2) should be in the numerator on the RHS

[edit: and the LHS too]
 
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Why? I took the stationary policeman as my intertial reference frame. To him L 1/sqrt(1-(1/2)^2) is the length of car 1 and 2L/sqrt(1-v^2/c^2) is the length of car 2. These quantities must be equal, right?
 
ehrenfest said:
Why? I took the stationary policeman as my intertial reference frame. To him L 1/sqrt(1-(1/2)^2) is the length of car 1 and 2L/sqrt(1-v^2/c^2) is the length of car 2. These quantities must be equal, right?

As olgran said that sqrt should be in the numerator on both sides. The length contracts... Can you explain the steps you took to get it in the denominator?
 
ehrenfest said:
Why? I took the stationary policeman as my intertial reference frame. To him L 1/sqrt(1-(1/2)^2) is the length of car 1 and 2L/sqrt(1-v^2/c^2) is the length of car 2. These quantities must be equal, right?

Nope. For example, to him the length of car one is

<br /> \frac{L}{\gamma(c/2)}\;.<br />

Which is *not* the same as what you have written.

Don't get your gammas upsidedown.
 
remember length contracts when moving and proper length is always biggest. and since \gamma \geq 1 always, you can quickly check whether your answer make sense or not... for \frac{L}{\gamma} \leq L
 
I see. So the velocity of car 2 must be sqrt(13/16)c, right?
 
ehrenfest said:
I see. So the velocity of car 2 must be sqrt(13/16)c, right?

yep.
 
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