What is the Velocity of the Second Ship Relative to the First Ship?

AI Thread Summary
To find the velocity of the second ship relative to the first, the equations V1 + r = V2 and V2 - V1 = r are used, where r represents the relative velocity. The approach involves breaking down the velocities into x and y components and calculating the resultant using the formula sqrt(x^2+y^2) for magnitude and tan-1(y/x) for direction. Participants confirm the correctness of this method and suggest using different variable names for clarity. The discussion highlights the importance of clear notation and understanding vector components in solving relative velocity problems. Overall, the method for determining the relative velocity is validated.
jwxie
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Homework Statement



Two ships, one moving 15 degree west of north with a speed 25 mi/h., the second moving 25 degree south of west with a speed 20 mi/h. relative to water pass each other. Find the velocity of the second ship relative to the first ship (magnitude and direction).

Homework Equations



V1 + r = V2
V2 - V1 = r

The Attempt at a Solution



I want to confirm on this.

My approach is using this relation.
V1 + r = V2
and so V2 - V1 = r, where r is the velocity we are looking for of our problem.

Then I will take components, x and y, and find sqrt(x^2+y^2) and direction tan-1 y/x
 
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Hi jwxie! :smile:

(have a square-root: √ and try using the X2 and X2 tags just above the Reply box :wink:)
jwxie said:
My approach is using this relation.
V1 + r = V2
and so V2 - V1 = r, where r is the velocity we are looking for of our problem.

Then I will take components, x and y, and find sqrt(x^2+y^2) and direction tan-1 y/x

Yes, that's exactly right! :smile:

(btw, I wouldn't use r, I'd stick to the same area of the alphabet, and use v12 or u or w :wink:)
 
Hi, tiny, thank you for your confirmation. My friend had an exam and he doubted about my explanation. Thank you!

I will make sure I check all the synatx ^^
 
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