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SenatorAstro
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Homework Statement
A limp rope with a mass of 2.4 kg and a length of 1.5 m is hung, initially at rest, on a frictionless peg that has a negligible radius, as shown in the Figure. y1 is equal to 0.48 m. What is the vertical velocity of the rope just as the end slides off the peg?
Homework Equations
PE = mgh
KE = 1/2mv^2
The Attempt at a Solution
Because the kinematics of this system seemed incredibly complicated, I figured it best to use conservation of energy in the system. Knowing that the center of mass will fall 0.48 meters, I assumed:
mgΔH = 1/2mv^2
2.4*9.81*0.48 = 1/2*2.4*v^2
v = 3.06881084461 m/s
Unfortunately, this seems to be incorrect.