What is the volume between two intersecting spheres with given equations?

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SUMMARY

The discussion focuses on calculating the volume of the solid that lies within two intersecting spheres defined by the equations x²+y²+z²=4 and (x+2)²+(y-1)²+(z+2)²=4. The centers of the spheres are located at (0,0,0) and (-2,1,-2), both with a radius of 2, and are 3 units apart. The solution involves using integration techniques to find the volume of intersection, analogous to finding the volume of two circles revolved around the x-axis. The participant successfully identifies the method to proceed with the calculation.

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Homework Statement



Find the volume of the solid that lies inside both the spheres
x^2+y^2+z^2=4
x^2+y^2+z^2+4x-2y+4z+5=0


Homework Equations



none

The Attempt at a Solution



I completed the square on the 2nd equation to get (x+2)^2 + (y-1)^2 + (z+2)^2 = 4

So I have the two centers (0,0,0) and (-2,1,-2) which are 3 units apart and both have a radius of two. I think I have to take an integral, but I don't know where to go from here. Thanks for any help
 
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That's a great start! Now pretend you have two circles of radius 2 with centers on the x-axis that are 3 units apart, say one centered at x=0 and one centered at x=3. Could you find the volume of their intersection revolved around the x-axis? That's the same as the volume you are looking for, isn't it?
 
Ohhh ok thank! I got it! :)))
 

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