What is the volume between two intersecting spheres with given equations?

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Homework Statement



Find the volume of the solid that lies inside both the spheres
x^2+y^2+z^2=4
x^2+y^2+z^2+4x-2y+4z+5=0


Homework Equations



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The Attempt at a Solution



I completed the square on the 2nd equation to get (x+2)^2 + (y-1)^2 + (z+2)^2 = 4

So I have the two centers (0,0,0) and (-2,1,-2) which are 3 units apart and both have a radius of two. I think I have to take an integral, but I don't know where to go from here. Thanks for any help
 
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That's a great start! Now pretend you have two circles of radius 2 with centers on the x-axis that are 3 units apart, say one centered at x=0 and one centered at x=3. Could you find the volume of their intersection revolved around the x-axis? That's the same as the volume you are looking for, isn't it?
 
Ohhh ok thank! I got it! :)))
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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