What is the work done by friction in a sliding mass on a 30 degree incline?

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A 2 kg mass slides down a 30-degree incline from a height of 10m, reaching a speed of 10 m/s at the bottom. To calculate the work done by friction, one must consider the difference between the initial potential energy and the final kinetic energy. The initial potential energy can be calculated using the formula mgh, while the final kinetic energy is determined using 0.5mv². The work done by friction represents the energy lost due to friction, which is the difference between these two energy states. Understanding energy conservation is key to solving this problem.
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Starting from rest and a height of 10m, a 2 kg mass slides down a 30 degree incline, reaching the bottom with a speed of 10 m/s. What is the approximate work done by friction? I don't know how to calculate the work done by friction , can someone help me please
 
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striving said:
Starting from rest and a height of 10m, a 2 kg mass slides down a 30 degree incline, reaching the bottom with a speed of 10 m/s. What is the approximate work done by friction? I don't know how to calculate the work done by friction , can someone help me please

What concept would you utilize here? You know the initial conditions and the final conditions.
 
Think in terms of energy conservation. At the top of the incline the mass had a certain potential energy due to gravity and its height. At the bottom of the incline it had a kinetic energy as dictated by its velocity.
 
so the work done by friction will be the energy difference between initial potential energy and final kinetic energy?
 
Where else would it go?
 
i hate to say that, but be honest i don't know
 
striving said:
so the work done by friction will be the energy difference between initial potential energy and final kinetic energy?

Yes, will give you the work done by friction.


striving said:
i hate to say that, but be honest i don't know
 
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