What is the work done by gas, given V, T and P

AI Thread Summary
To calculate the work done by gas during an isobaric process, the relevant equation is W = PΔV, where P is the constant pressure and ΔV is the change in volume. Given the initial volume of 0.5 m³ and the final volume calculated as 0.683 m³, the change in volume (ΔV) is 0.183 m³. With a pressure of 3·10^5 Pa, the work done can be computed as W = 3·10^5 Pa * 0.183 m³, resulting in the work done by the gas during heating. Understanding that pressure multiplied by volume gives energy in joules is crucial for solving these types of problems. This approach effectively demonstrates the relationship between pressure, volume, and work in thermodynamic processes.
arddi2007
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Homework Statement



0.5 m3 of air is located in a vessel. Their temperature is T1=0oC and the pressure is p=3·105. What work will be done when heating the gas with constant pressure (isobaric process) to T2=100oC?

Homework Equations



I was unable to find any equation regarding to the work done by gases. This is a part of physics I'm not so good at. But these equations might be useful too:

Isobaric process (with constant pressure):

V1/T1=V2/T2

From that equation we can find the value of V2.

The Attempt at a Solution



V1/T1=V2/T2
V2=V1T2/T1

After converting and substituting the values, we get the value of V2:

V2=0.683 m3.

Still, I am unable to find any relevant equation for work done by gases and I would appreciate any help. Thank you very much!
 
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arddi2007 said:
Still, I am unable to find any relevant equation for work done by gases and I would appreciate any help.

The work done is W=\int P\,dV. You really couldn't even find this with an Internet search?
 
It's handy to remember, in terms of the units involved, that the product of pressure and volume yields energy. That is, N/m2 x m3 --> Nm --> Joules.

So if pressure is kept the same, the work done will be PΔV.
 
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